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0.8x^2-3.4x+1.8=0
a = 0.8; b = -3.4; c = +1.8;
Δ = b2-4ac
Δ = -3.42-4·0.8·1.8
Δ = 5.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.4)-\sqrt{5.8}}{2*0.8}=\frac{3.4-\sqrt{5.8}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.4)+\sqrt{5.8}}{2*0.8}=\frac{3.4+\sqrt{5.8}}{1.6} $
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